solve it and Give the answe
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Hi Mate!!
2 ^x = 3^y = (3 ×2)^z
2^x = 2^z = 3^y= 3^z
x = z. , y = z
1/x + 1/y +1/z = 1/z + 1/ z + 1/z
= 3 /z
Hope it helps...
2 ^x = 3^y = (3 ×2)^z
2^x = 2^z = 3^y= 3^z
x = z. , y = z
1/x + 1/y +1/z = 1/z + 1/ z + 1/z
= 3 /z
Hope it helps...
ayush6743:
But the answer given is 2/z
Ok thanks
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