Question

Solve it and help me

Answer 1

Step-by-step explanation:

angle a = 80

AS AD BISECTS ANGLE A THAN ANGLE BAD = 40

THEN ANGLE ADB = 95

ANGLE ADC = 85

Answer 2

Answer:

∠ADC    = 85° and ∠ADB   = 95°

Step-by-step explanation:

The sum of all angles of a triangle is equal to 180°

In ΔABC,

∠B + ∠C + ∠BAC = 180°

45° + 55° + ∠BAC = 180°

100° + ∠BAC = 180°

∠BAC = 180° - 100°

∠BAC = 80°    

∠CAD + ∠BAD = ∠BAC

But, ∠CAD = ∠BAD.

⇒∠CAD + ∠CAD = 80°

⇒ 2∠CAD = 80°

⇒∠CAD  = 80° / 2

∠CAD = 40°

∠CAD = ∠BAD =  40°

In ΔADC,

∠ADC + ∠C + ∠DAC = 180°

∠ADC + 55° + 40° = 180°

∠ADC + 95°  = 180°

∠ADC    = 180° - 95°

∠ADC    = 85°

∠ADB + ∠ADC = 180°   ...   Linear pair

∠ADB + 85° = 180°

∠ADB   = 180° - 85°

∠ADB   = 95°

So, ∠ADC    = 85° and ∠ADB   = 95°