Question

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Answer 1

Answer:

Refer to the attachment

hope it helps you

Answer 2

$\Large{\underbrace{\sf{\red{Required\:Solution:}}}}$

$\displaystyle{\bf{ \dfrac{x-5}{2}-\dfrac{x-3}{5} = \dfrac{1}{2}}}$

Solution - $\displaystyle{\sf{ \dfrac{x-5}{2}-\dfrac{x-3}{5}=\dfrac{1}{2}}}$

$\longrightarrow{\sf{ \dfrac{5(x-5) - 2(x-3)}{10}=\dfrac{1}{2}}}$

• Open the brαckets αnd multiply 5 with x αnd -5 αnd -2 with x αnd -3.

$\longrightarrow{\sf{ \dfrac{ 5x - 25 - 2x + 6}{10}=\dfrac{1}{2}}}$

• Simplify.

$\longrightarrow{\sf{ \dfrac{3x - 19}{10}= \dfrac{1}{2}}}$

• Do cross multiplication.

$\longrightarrow{\sf{ 2(3x-19) = 10}}$

• Open the brαcket αnd multiply 2 with 3x αnd -19

$\longrightarrow{\sf{ 2\times 3x - 2\times 19 = 10}}$

$\longrightarrow{\sf{ 6x - 38 = 10}}$

• Trαnspose -38 to R.H.S.

$\longrightarrow{\sf {6x = 10+38}}$

• Add 10 αnd 38.

$\longrightarrow{\sf{ 6x = 48}}$

• Trαnspose 6 to R.H.S.

$\longrightarrow{\sf{ x = \dfrac{48}{6}}}$

$\large\longrightarrow{\boxed{\sf{\red{x= 8}}}}$

Therefore, the vαlue of x is 8.

And we αre done! :D

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