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Answered by
1
Step-by-step explanation:
Answer
Let OP be any line through the origin O which has direction cosines l,m,n.
Let P be the point having coordinates (x,y,z) and OP=r.
Then OP
2
=x
2
+y
2
+z
2
=r
2
...(1)
From P draw PA,PB,PC perpendicular on the coordinate axes, so that OA=x,OB=y,OC=z
Also, ∠POA=α,∠POB=β,∠POC=γ
From triangle AOP,l=cosα=
r
x
⇒x=lr
Similarly, y=mr,z=nr
Adding all we getx
2
+y
2
+z
2
=r
2
(l
2
+m
2
+n
2
)
⇒r
2
=r
2
(l
2
+m
2
+n
2
)
⇒l
2
+m
2
+n
2
=1
Answered by
2
Step-by-step explanation:
9).Answer :- i). l:m = 1¼
Hope its help..
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