Math, asked by sunitasaini53143, 10 months ago

solve it anyone please​

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Answered by devikasibi123
2

Answer:

10

Step-by-step explanation:

Given Without using tables , evaluate 4tan60° sec30° + sin 31°sec59° + cot59°cot 31°/8sin^2 30° - tan^2 45°

4 tan 60 sec 30 + sin 31 sec 59 + cot 59 cot 31 / 8 sin²30 - tan²45

4 tan 60 sec 30 + sin 31 sec(90 - 31) + cot 59 cot(90 - 59) / 8 sin²30 - tan²45

4 tan 60 sec 30 + sin 31 cosec 31 + cot 59 tan 59 / 8 sin²30 - tan²45

4 tan 60 sec 30 + sin 31 x 1 / sin 31 + cot 59 x 1 /cot 59 / 8 sin²30 - tan²45

4 x √3 x 2 /√3 + 1 + 1/8 x 1/4 - 1)

4 x 2 + 1 + 1

8 + 2 = 10

Answered by Anonymous
1
  1. Answer: 10 Step-by-step explanation: 1. 4tan60Sec30     4 x sqrt{3} x 2/sqrt{3}       4 x 2 = 8  2. Sin31 x Sec59 + Cot59 x Cot 31      Sin31/Cos59 + Cot59/Tan31      Sin31/Sin(90-59) + Cot59/Cot(90-31)     Sin31/Sin31 + Cot59/Cot59     1 + 1     2  3. 8Sin^{2}30 - Tan^{2}45      8 x 1/4 - 1     2 - 1     1   ⇒ 8 +2/1 = 10  
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