Math, asked by sharmaurmil97, 1 day ago


Solve it as soon as possible I will wait for your lovely response​

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Answers

Answered by djtigerking75
0

Answer:

Give(cosA−sinA)(secA−CosA)=

tanA+cotA

1

L.H.S.(coscA sinA)(secA-cosA)

⇒L.H.S=(

sinA

1

−sinA)(

cosA

1

−cosA)

⇒L.H.S=(

sinA

1−sin

2

A

)(

cosA

1−cos

2

A

)

⇒L.H.S=

sina.cosA

cos

2

A.sin

2

A

[∵sin

2

A+cos

2

A−1cos

2

A−1−sin

2

Asin

2

A=1−cos

2

A]

⇒L.H.S=

1

sinA.cosA

⇒L.H.S=

sin

2

A+cos

2

A

sinA.cosA

⇒L.H.S=

sinA.cosA

sin

2

A+cos

2

A

1

⇒L.H.S=

sinAcosA

sin

2

A

+

sinA.cosA

cos

2

A

1

⇒L.H.S=

cosA

sinA

+

sinA

cosA

1

⇒L.H.S=

tanA+cotA

1

=R.H.S

⇒L.H.S = R.H.S

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