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angle BAC =angle BDC=30° [ angles subtended by the same chord on the circumference of the circle are equal]
angle DCB+ angleDCX=180°. [linear pair]
angle DCB=95°
In triangle DBC
angleDCB + angleCBD + angleBDC=180°. [the sum of all the interior angles of a triangle is 180°]
angleCBD=x=55°
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Answer:
angles form in same segment are equal so
/A =/D
30°=/D
85°+/BCD =180°(linear pair)
/BCD =180°-85°
/BCD =95°
means /C =95°
Now in ΔBCD
/B +/C +/D =180°
x +95°+30°=180°
x +125°=180°
x =180°-125°
x =55°
100% correct answer
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