solve it !ASAP! ATHS ARYABHATTA
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Take 1 in left side you will get
x-1=(2^1/3+2^2/3)
Cubing both sides,
(x-1)^3=(2^1/3+2^2/3)^3
Applying Identity (a-b)^3=a^3-b^3-3ab(a-b)
x^3-1-3x(x-1)= 2+4+3×2(x-1)
x^3-1-3x^2+3x= 6+6x-6
x^3-3x^2-3x-1=0
Hence Proved
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