Question

solve it bro plsee solve​

Answer 1

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \boxed{\boxed { \huge \mathcal\red{ solution}}}}$

$\implies \frac{d}{dx} ( \sqrt{x} + \frac{1}{ \sqrt{x} } ) {}^{2} \\ \implies \frac{d}{dx} (( \sqrt{x}) {}^{2} + ( \frac{1}{ \sqrt{x} } ) {}^{} {}^{2} + 2 \times \sqrt{x} \times \frac{1}{ \sqrt{x} } \\ \implies \frac{d}{dx} (x + \frac{1}{x} + 2) \\ \implies \frac{d}{dx}(x) + \frac{d}{dx} ( \frac{1}{x} ) + \frac{d}{dx} (2) \\ \implies1 + ( -1 )(x {}^{ - 2} ) + 0 \\ \implies \boxed{1 - \frac{1}{x {}^{2} } }$

Ans:-So option (b)(1-1/x²)

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•Related Formulas

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$\rightarrow \frac{d}{dx} (x {}^{n} ) = n \times x {}^{n - 1} \\ \rightarrow \frac{d}{dx} (c) = 0 \: \: \: ( \because \: c = constant) \\ \rightarrow \frac{d }{dx} (u&#8723;v&#8723;</p><p>w&#8723;......) = \frac{du}{dx} &#8723; \frac{dv}{dx} &#8723; \frac{dw}{dx} &#8723;........</p><p> \\ where \: u \: and \: v \: and \: w \: and \: .....are \: \\ function \: of \: x</p><p></p><p></p><p></p><p>$

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Answer 2

Step-by-step explanation:

d/dx(√x+1/√x)²

d/dx(x+1/x+ 2√x1/√x)

d/dx(x+1/x+2)

d/dx(x²+1+2x)/x

d/dx×x²+1+2x/x

=dx²+dx+2dx/dx²

3dx