Question

solve it bro / sis.........?

Answer 1

Hey...mate here is yur ans...
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⏩ Initial position of wire = AOB. final position of wire = ACB Let $\theta$be the angle made by wire with horizontal, which is very small.

⏩ Resolving tension T of string in horizontal and vertical directions, we note that the horizontal components cancel while vertical components add and balance the weight. For equilibrium

2T sin(theta) = W = mg :: T = W / 2 sin$\theta$

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HOPE IT HELPS U ✌

Answer 2

2Tsin theta =mg

T=mg/2sin theta