Question

Solve it:But don't spam ​

Answer 1

Step-by-step explanation:

Answer:-

Given:-ABC=x°,CDE=3x°,BCD=86°

To find:- x

Draw a line FG Parallel to AB and DE through C.

Now, AngleBCG=Angle ABC(by.alt.int.∆s)

BCG=x

And,

AngleDCG+AngleCDE=180° (Sum of angle on same side of a Parallel is 180°)

Angle DCG=180-x.

Given,

AngleBCD=AngleBCG+Angle DCG

==>x+180-3x=86

==>180-2x=86

==>2x=180-86

==>2x=94

==>x=94.

hope it will help you dear

Answer 2

Answer:

only figure spamed becose

l can not draw figure from

mobile

Step-by-step explanation:

angleABF = angleEFC (alternative interior angl)

sideAB||sideEF

given that,

angleBCD = 86°

angleCDE = 3X

.. angleFCD = 180° - 86°

= 94°

and angleFDC = 180° - 3x

In CFD,

angleCFD + angleFDC + angleFCD = 180°

X + 180° - 3x + 94° = 180°

2x = 94°

so, x = 47° answer