Math, asked by junini, 1 year ago

solve it by cross multiplication method....​

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Answered by divii25
2

Answer:

2x + 5y -1 = 0 ( a1 = 2 b1 = 5 c1 = -1) _______ eq 1

2x + 3y -3 =0 ( a2 = 2 b2 = 3 c2 = -3) ______eq 2

BY CROSS MULTIPLICATION METHOD

x / b1c2 - b2c1 = y / c1a2 - c2a1 = 1 / a1b2 - a2b1

Putting the values

x / 5×-3 - 3× -1 = y / 2× -1 - ( -3) ×2 = 1 / 2×3 - 2×5

Simplifying the values

x / -12 = y / 4 = 1 / -4

x / -12 = 1/ -4 y / 4 = 1 / -4

x = 3 y = -1

THEREFORE, x = 3 and y = -1

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Answered by shhxdjaln
4

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refer to the attachment!!

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