solve it by Cross multiplication method only....
please help me ....
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Answered by
14
HELLO DEAR,
let
1/(x-1)=P-----------(1)
1/(y-2)=q------------(2)
now the new Equation will be:-
5p+q=2-----------(3)
6p-3q=1----------(4)
from--(3)&(4)
multiply by (3) in (3)
we get,
15p+3q=6
6p-3q=1
________
21p=7
P=1/3
Put in (4)
We get,
6*1/3-3q=1
2-3q=1
3q=1
q=1/3
From--(1)
P=1/3=1/x-1
3=x-1
X=4
From--(2)
q=1/3=1/y-2
3=y-2
Y=5 and x=4
I HOPE ITS HELP YOU DEAR,
THANKS
let
1/(x-1)=P-----------(1)
1/(y-2)=q------------(2)
now the new Equation will be:-
5p+q=2-----------(3)
6p-3q=1----------(4)
from--(3)&(4)
multiply by (3) in (3)
we get,
15p+3q=6
6p-3q=1
________
21p=7
P=1/3
Put in (4)
We get,
6*1/3-3q=1
2-3q=1
3q=1
q=1/3
From--(1)
P=1/3=1/x-1
3=x-1
X=4
From--(2)
q=1/3=1/y-2
3=y-2
Y=5 and x=4
I HOPE ITS HELP YOU DEAR,
THANKS
Aasthakatheriya1:
thnks but I am say to solve it by Cross multiplication method
Answered by
5
hlooo...aastha..
Ur anawer is in the above picture..
hope this helps!!!!!!
Ur anawer is in the above picture..
hope this helps!!!!!!
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