Math, asked by VishalAdhikari, 11 months ago

solve it by elimination 44a+30b=10 55a+40b=13

Answers

Answered by hemalathakalyani
5

Answer: a= 1/11, b = 1/5

Step-by-step explanation:

equatio

44a+30b = 10

multiply 4 on both sides

4(44a+30b) = 4*10

176a+120b = 40....equation 1

55a+40b = 13

multiply 3 on both sides

3*(55a+40b) = 13*3

165a+120b = 39...equation 2

equation 1 - equation 2

(176a+120b)-(165a+120b) = 40-39

176a+120b-165a-120b = 1

11a = 1

a = 1/11

substitute in 55a+40b = 13

  55(1/11)+40b = 13

    5+40b = 13

40b = 13-5

  40b = 8

  b = 1/5

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