Question

solve it by elimination method

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Answer 1

Answer:

x=4 and y= -4

Step-by-step explanation:

For first eq.

By taking LCM:

$\frac{32 + x - y}{8} = 17$

$33x - y = 136................(1)$

And,

$\frac{6y + 3x - 5y + 2}{3} = 2 \\ 6y + 3x - (5y + 2) = 6 \\ 6y + 3x - 5y - 2 = 6 \\ 3x + y = 8$

Two equations with us are:

$33x - y = 136 \\ 3x + y = 8..........(2)$

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$36x = 144$

Therefore x=4

Now putting the value of x in eq 2

$3 \times 4 + y = 8 \\ y = - 4$

Therefore,

x= 4 and y= -4