Question

solve it by factorization method ​

Answer 1

$y^2+\frac{3\sqrt{5}y }{2}-5= 0\\  2y^2+3\sqrt{5}y-10= 0\\  2y^2+4\sqrt{5}y -\sqrt{5}y -10= 0\\2y(y+2\sqrt{5})-\sqrt{5}(y+2\sqrt{5})= 0\\   (2y-\sqrt{5})(y+2\sqrt{5})= 0\\  y= \sqrt{5}/2 \\ y= -2\sqrt{5}$

[The given eqⁿ is multiplied with 2 on both sides.]

#Sum of the zeroes = - (coefficient of x) ÷ coefficient of x2

α + β = - b/a

(- 2√5) + (√5/2) = - (3√5)/2

- 3√5/2 = - 3√5/2     {LHS = RHS}

# Product of the zeroes = constant term ÷ coefficient of x2

α β = c/a

(- 2√5)(√5/2) = - 5

- 5 = - 5      {LHS = RHS}

Hope it helps..