solve it by factorization method √3xsquare -2√2x-2√3=0
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√3 x² - 2√2 x - 2√3 = 0
Multiplying √3 and 2√3 = 6
now, split this in such a way that it's sum of difference will be -2√2
i.e. -3√2 +√2 = -2√2
√3 x²-3√2x +√2x -2√3 =0
=√3x(x -√6) +√2(x -√6) =0
=(x-√6)(√3x +√2) =0
So, (x-√6)=0 or (√3x +√2) =0
x = √6 or x= -√(2/3)= -√6/3
Multiplying √3 and 2√3 = 6
now, split this in such a way that it's sum of difference will be -2√2
i.e. -3√2 +√2 = -2√2
√3 x²-3√2x +√2x -2√3 =0
=√3x(x -√6) +√2(x -√6) =0
=(x-√6)(√3x +√2) =0
So, (x-√6)=0 or (√3x +√2) =0
x = √6 or x= -√(2/3)= -√6/3
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