Question

solve it by factorization method
5(3x+1) ^2+6(3x+1) -8=0​

Answer 1

let 3x +1 = t

= 5t^2 + 6t - 8 = 0

= 5t^2 + 10t - 4t - 8 = 0

= 5t(t + 2) -4(t+2) = 0

= (5t-4)(t+2) = 0

= t = 4/5 , -2

3x+1 = 4/5

x = -1/15

3x + 1 = -2

x = -1

x = -1, -1/15