Question

solve it by linear equations ​

Answer 1

$\Large{\underbrace{\sf{\orange{Required\:Solution:}}}}$

$\displaystyle{\sf{ \dfrac{4x-3}{2x+6} = \dfrac{3}{2}}}$

• Do cross multiplication.

$\implies{\sf{ 2(4x - 3) = 3(2x + 6)}}$

• Open the brackets and multiply the numbers.

$\implies{\sf{8x - 6 = 6x + 18}}$

• Transpose -6 to R.H.S.

$\implies{\sf{8x - 6x = 18 + 6}}$

• Transpose 2 to R.H.S.

$\implies{\sf{2x = 24}}$

• Divide this.

$\implies{\sf{x = \dfrac{24}{2}}}$

$\large{:}\implies{\boxed{\sf{\orange{x = 12}}}}$

__________________________

Answer 2

Required Solution :-

Here we need to calculate the value of x.

So let's start !

>> 4x - 3 / 2x + 6 = 3/2

Simply cross multiplying them,

>> 2 (4x - 3) = 3 (2x + 6)

>> 2 × (4x - 3) = 3 × (2x + 6)

>> 8x - 6 = 6x + 18

>> 8x = 6x + 18 + 6

>> 8x = 6x + 24

>> 8x - 6x = 24

>> 2x = 24

>> x = 24 / 2

>> x = 12

Therefore, value of x is 12 !