Question

solve it by subsitution method ..........​

Answer 1

Answer:

x+y =13

Step-by-step explanation:

x/3 + y/2 = 13/6

x/3 + y = 13/6 ×2

x + y = 13/3 × 3

x + y = 13

Answer 2

Step-by-step explanation:

Given equations:-

$\sf \dfrac{3x}{2} - \dfrac{5y}{3} = - 2.....(i)$

$\sf \dfrac{x}{3} + \dfrac{y}{2} = \dfrac{13}{6} .......(ii)$

In equation (i)

$\sf \dashrightarrow \dfrac{3x}{2} - \dfrac{5y}{3} = - 2$

$\sf \dashrightarrow \dfrac{3(3x) - 2(5y)}{6} = - 2$

$\sf \dashrightarrow \dfrac{9x - 10y}{6} = - 2$

$\sf \dashrightarrow 9x - 10y = - 2(6)$

$\sf \dashrightarrow 9x - 10y = - 12$

$\sf \dashrightarrow 9x = - 12 + 10y$

$\sf \dashrightarrow x = \dfrac{10y - 12}{9}......(iii)$

$\sf Substituting \: x = \dfrac{10y - 12}{9} \: in \: equation \: (ii)$

$\sf \dashrightarrow\dfrac{x}{3} + \dfrac{y}{2} = \dfrac{13}{6}$

$\sf \dashrightarrow\dfrac{ \bigg(\: \: \: \dfrac{10y - 12}{9 } \bigg) }{3} + \dfrac{y}{2} = \dfrac{13}{6}$

$\sf \dashrightarrow\dfrac{ 10y - 12 }{27} + \dfrac{y}{2} = \dfrac{13}{6}$

$\sf \dashrightarrow\dfrac{ 2(10y - 12) + 27y }{54} = \dfrac{13}{6}$

$\sf \dashrightarrow\dfrac{ 20y - 24 + 27y }{54} = \dfrac{13}{6}$

$\sf \dashrightarrow 47y - 24 = \dfrac{13}{6} \times 56$

$\sf \dashrightarrow 47y - 24 = 117$

$\sf \dashrightarrow 47y = 117 + 24 = 141$

$\sf \dashrightarrow y = \dfrac{141}{47} = 3$

$\sf Substituting \: y = 3\: in \: equation \:(iii)$

$\sf \dashrightarrow x = \dfrac{10y - 12}{9}$

$\sf \dashrightarrow x = \dfrac{10(3) - 12}{9}$

$\sf \dashrightarrow x = \dfrac{18}{9} = 2$

$\dashrightarrow \underline{\boxed{\sf \therefore x = 2 \: , \: y = 3}}$