Question

solve it by substituting method​

Answer 1

TO SOLVE THE EQUATION BY SUBSTITUTION METHOD :-

$\sqrt{2} x + \sqrt{3} y = 0 ...eq.01\\ \\ \sqrt{3} x - \sqrt{8} y = 0...eq.02$

SOLUTION

First we will equate the value for x in terms of y in equation 01 ;

$\sqrt{2} x + \sqrt{3} y = 0 \\ \\ \\ \implies \sqrt{2} x = - \sqrt{3} y \\ \\ \\ \implies x = \frac{ - \sqrt{3}y }{ \sqrt{2} }$

Substituting the value of x in eq. 02

$\sqrt{3} x - \sqrt{8} y = 0 \\ \\ \\ \implies\sqrt{ 3} \times \frac{ - \sqrt{3}y }{ \sqrt{2} } - \sqrt{8y } = 0 \\ \\ \implies -\frac{3y}{\sqrt{2}}-\sqrt8y =0 \\ \implies -3y-\sqrt{16} =0\\\\ \\ \implies -3y - 4y = 0 \\ \\ \\ \implies -7y =0 \\ \\ \\ \implies y = 0$

Putting this value in eq. 01

$\sqrt{2} x + \sqrt{3} y = 0 \\ \\ \\ \implies \sqrt{2} x + \sqrt{3} \times 0 = 0 \\ \\ \\ \implies \sqrt{2} x = 0 \\ \\ \\ \implies \ \boxed{ x = 0}$

Hence x = 0 and y = 0 (ANS)