Question

solve it by substitution method 5x-6y=-23, 10x+7y=30​

Answer 1

Answer:

x = ⅕

y = 4

Step-by-step explanation:

Given a pair of linear equations

5x - 6y = -23 ........(1)

10x + 7y = 30 .........(2)

Solving eqn (1) , we get,

=> 5x = 6y - 23

Now, substitute this value in (2),

Therefore, we will get,

=> 2(5x) + 7y = 30

=> 2(6y -23 ) + 7y = 30

=> 12y - 46 + 7y = 30

=> 19y = 46 + 30

=> 19y = 76

=> y = 76/19

=> y = 4

Therefore, we will get,

=> 5x = 6×4 - 23

=> 5x = 24 - 23

=> 5x = 1

=> x = 1/5

Hence ,the values of x = ⅕ and y = 4.

Answer 2

5x-6y=-23

10x+7y=30

:- 5x-6y=-23 -(1)

10x+7y=30 -(2)

Step 1=> From (1):-

5x=-23+6y

x=(-23+6y)÷5 -(3)

Step 2=> Substitute (3) in (2)

10×(-23+6y)÷5 +7y=30

2×(-23+6y) +7y= 30

-46+12y+7y=30

-46+19y=30

19y=30+46

19y=76

y=76÷19

y=4

Use value of y in (3)

x=(-23+6×4)÷5

x=(-23+24)÷5

x=1/5 or x=0.2

Solution is x=2, y=3.

Hope it helps you,

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