Question

Solve it by using factorisation of algebraic expression 4(x-y)+8(y-x)²

Answer 1

Step-by-step explanation:

$4x - 4y + 8(y {}^{2} +x {}^{2} - 2xy) \\ 4x - 4y + 8y {}^{2} + 8x {}^{2} - 16xy \\( 8x { }^{2} + 4x) + (8y {}^{2} - 4y) - 16xy \\ 4x(2x + 1) + 4y(2y - 1) - 16xy \\( 2x + 1) + (2y - 1) - 4xy$

I hope this help you.

Answer 2

The correct answer is "8x²+8y²+4x-4y-16xy".

Step-by-step explanation:

$The \ given \ expression \ is:\\\\4(x-y)+8(y-x)^2\\\\As \ we \ know,\\\\(a-b)^2=a^2+b^2-2ab\\\\On \ applying \ this \ formula,we \ get\\\\=4(x-y)+8(y^2+x^2-2xy)\\\\On \ applying \ multiplication,we \ get\\\\=4x-4y+8y^2+8x^2-16xy\\\\=8x^2+8y^2+4x-4y-16xy$

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