Question

solve it correct answer will be brainliest​

Answer 1

$\\\fbox{\fbox{\fbox{\fbox{\fbox{\huge{\underline{\underline{\sf{\pink{Answer}}}}}}}}}}$

Angle 1 = ${28}^{\circ}$

x = ${62}^{\circ}$

$\\\fbox{\fbox{\fbox{\fbox{\fbox{\huge{\underline{\underline{\sf{\green{Solution}}}}}}}}}}$

Since ABCD is a square, all angles at the corners are 90°.

So,

$\sf \angle \: B$ = 90°

$\sf \angle \: B$ = (x + 28)°

Therefore,

x° + 28° = 90°

x° = 62°

To find Angle 1, there are two ways:

Let angle 1 be y.

Way 1:

In square ABCD, there are two triangles.

In triangle ABD,

We know that sum of all angles in a triangle is 180°.

y + x + 90° = 180°

y + 62° = 90° [ x = 62° from above]

y = 28°

Way 2:

We know that, from interior alternate angle y and 28° are equal.

So, y = 28°

$\\\fbox{\fbox{\fbox{\fbox{\fbox{\huge{\underline{\underline{\sf{\red{Hope\:it\:helps}}}}}}}}}}$

Answer 2

Answer:

are u got mad

to delete account

I kill u if u delete ur account did ur hear