Question

Solve it correctly and get 200 points!!!! Find factors of p^6+p^3-p^2+p-1. Explain in detail. (Ch-1 Number system class 9).

Answer 1

Answer:

hiya friend

Step-by-step explanation:

p⁶+ p³ - p² +p -1

p³(p³+1) - p² + p - 1

p³(p³+1³) - p² + p - 1

p³ (p+1) (p²-p+1) - 1 (p²-p+1)

(p²-p+1) [p³(p+1) -1]

(p²-p+1) (p⁴+p³-1)

we know that a³+b³ = (a+b) ( a²+b²-ab) in (p³+1)

hope the answer will be helpful for you

BTW in which school u are