solve it correctly please
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Given,
5^x = 3^y = 45^z
Let us 5^x = 3^y= 45^z = m
And 5 = m^1/x, 3 = m^1/y, 45 = m^1/z
So, 45^z = m
m^1/z = 45
m^1/z = 9 × 5 = 3×3 × 5 = 3² × 5
m^1/z = 3² × 5
m^1/z = (m^1/y)² × m^1/x
m^1/z = m^2/y × m^1/x
Since, Base is same of both side
Therefore, 1/z = 2/y + 1/x
Answer.
Thanks!
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