Math, asked by sahanakhan220, 5 months ago

Solve it
dy/dx=e^x-y+e^2logx-y

Answers

Answered by samithkv11
0

dx/day =e^x−y +e^2log x−y

⇒e^y dy=(e^x+x^2)dx
⇒e^y =e^x+x^3/3+c
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