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LHS = cos⁴ - cos²A
= cos²A( cos²A - 1 )
= ( 1 - sin²A )[ -( cos²A ) ]
= ( 1 - sin²A )( - sin²A )
= - sin²A + sin⁴A
= sin⁴ - sin²A
= RHS
Answered by
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L.H.S
Cos⁴A-Cos²A
Cos²A(Cos²A-1)
(1-sin²A){(1-Sin²A)-1}
(1-sin²A)(1-Sin²A-1)
(1-Sin²A)(-Sin²A)
-Sin²A+Sin⁴A
Sin⁴A-Sin²A = R.H.S
hence proved !
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