Question

Solve it fast................

Answer 1

hope it helps..................

Answer 2

We know that tangent are Perpendicular to the radius drawn to the point of contact

<ABC = 90°

Now,

OE bisects the chord AP

So, OE is Perpendicular to AP

<AEO = 90°

Now, in triangle ABC and AEO

<AEO = <ABC (each 90°)

< BAC = <EAO (common)

So,
Triangle ABC ~ AEO ( A. A. similarity)