Question

solve it fast..........
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Answer 1

${2}^{x - 1} = 4 \\ {2}^{x - 1} = {2}^{2}$
$in \: this \: case \: we \: can \: write \\ x - 1 = 2 \\ x = 2 - 1 \\ x = 1 \\ second$
${3}^{y - 2} = 9$
$= > {3}^{y - 2} = {3}^{2} \\ again \: we \: can \: write \\ y - 2 = 2 \\ y = 2 + 2 \\ y = 4$

x=1 and y=4.
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