Question

Solve it fast & also explain the sum in detail.
$\cos(what) = 0$
$[[Don't Copy & Paste]]$
​

Answer 1

✨HEYA MATE!!✨

Answer:

1

Step-by-step explanation:

Cos θ = Adjacent Side / Hypotenuse Side

Value of Cos 0 Using Unit Circle

Assume a unit circle with the center at the origin of the coordinate axes. Consider that P (a, b) be any point on the circle which forms an angle AOP = x radian. This means that the length of the arc AP is equal to x. So we define that cos x = a and sin x = b

Now consider a triangle OMP is a right triangle,

By using the Pythagorean theorem, we get

OM2+ MP2= OP2 (or) a2+ b2= 1

So for every point on the unit circle, we define it as

a2+ b2 = 1 (or) cos2 x + sin2 x = 1

It is noted that the one complete revolution subtends an angle of 2π radian at the centre of the circle,

∠AOB=π/2,

∠AOC = π and

∠AOD =3π/2.

Since all angles of a triangle are the integral multiples of π/2 and it is commonly called quadrantal angles. Therefore, the coordinates of the points A, B, C and D are (1, 0), (0, 1), (–1, 0) and (0, –1) respectively. Therefore, from the quadrantal angles, we can get the cos 0 value

Cos 0° = 1

Answer 2

Answer:

cos 90 ° is zero

Step-by-step explanation:

cos theta is adjacent side by hypotenuse

only when adjacent side becomes zero cos theta becomes zero

therefore the angle is 90°