Question

solve it fast and don't give unnecessary answers solve both the questions
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Answer 1

Answer:

Initial velocity of the ball final velocity =0m/s

acceleration due to gravity (g)=−10m/s

2

(upward motion)

By using the formula,

v=u+at

O=25+(−10)×t

10t=25

t=2.5sec.

The time taken for upward journey is equal to the time taken for downward journey.

Therefore, total time taken by the ball =2.5+2.5=5sec.

Answer 2

Explanation:

$velocity \: of \: the \: ball(u) = 25m {s}^{ - 1} \\ \\ g = 10m {s}^{ - 2}$

man throws the ball vertically upwards

so the formula to travel distance

$h = ut - \frac{1}{2} g {t}^{2}$

t = 2 sec

$h = 25 \times 2 - \frac{1}{2} \times 10 \times {2}^{2} \\ = 50 - 20 = 30 \\ \\ h = 30m$

ball has been thrown upward so the final velocity of the ball is 0

v = 0

$v = u - gt \\ = > 0 = 25 - 10t \\ = > t = 2.5second$