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Step-by-step explanation:
The Formulas to be used in this Questions are:=>cos(90 - x) = sin x e.g. cos 22 = cos(90-68)= sin 22
=>tan(90 - x) = cot x e.g. cot 15 = cot(90-75) = tan 15
=>tanx.cotx = 1
Now Question is,
2sin68/cos22 - 2cot15/5tan75 - (3/5)tan45 tan20 tan40 tan50 tan70
=2sin68/sin68 - 2tan75/5tan75 - (3/5)1 tan20 tan40 cot40 cot 20
=2 - 2/5 - 3/5= 1
This is the Answer
Ritiksuglan:
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Hey mate here is your answer.
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