Question

solve it fast I want just now any one do ​

Answer 1

(1+i)1-i)^-1

1+i / 1-i = 1+i / 1-i × 1+i / 1-i

(1+i)^2 / 1->^2 = 1+2i + i^2 / 1-i^2

= 1+2i-1 / 1+1

2i/ 2 = i

=0+i