Question

solve it fast in a copy

Answer 1

Heya...!!!

HERE IS YOUR ANSWER

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x²-x-6
x²-(3-2)x-6
x²-3x+2x-6
x(x-3)+2(x-3)
(x-3) (x+2)

➡x-3 = 0
▶x = 3◀

➡x+2= 0
▶x = -2◀

So the zeroes are 3 and -2.

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HOPE IT HELPS!!!

Answer 2

$\blue{\huge{\boxed{\star\: Solution \: \star}}}$

To find zeros of
$x {}^{2} - x - 6$

$\red{ \boxed{ by \: middle \: term \: splitting}}$

==>
$x {}^{2} - 3x + 2x - 6$

===> x ( x - 3) +2 (x-3)=0

===> (x - 3) & (x + 2) =0

====> x =3 & x =-2


$\green{ \boxed{\underline{ zeros \: are \: 3 \: and \: - 2}}}$