Question

solve it fast... irrelevant and scammed answer will be reported


Great and true answers will be brainliest


(^_^)​

Answer 1

Answer:

1/2

Step-by-step explanation:

AB ⊥ AD and AB ⊥ CB ⇒ AD║CB

∠ ACD ≅ ∠ ADB and ∠ BAC ≅ ∠ ABD ⇒ Δ ACB ~ Δ BDA (AAA postulate)

$A_{BDA}$ = $\frac{8*AB}{2}$ = 4AB

$A_{ACB}$ = $\frac{4*AB}{2}$ = 2AB

$\frac{A_{ABC}}{A_{ADB}}$ = $\frac{2AB}{4AB}$ = $\frac{1}{2}$