Question

solve it fast my brothers​

Answer 1

Step-by-step explanation:

$\frac{(x+y)}{(x-y)} - \frac{(x-y)}{(x+y)} + \frac{4xy}{(x²+y²)} - \frac{8x³y}{(x⁴+y⁴)}$

$\frac{(x+y)²-(x-y)²}{(x-y)(x+y)} + \frac{4xy}{(x²+y²)} - \frac{8x³y}{(x⁴+y⁴)}$

$\frac{4xy}{(x²-y²)} + \frac{4xy}{(x²+y²)} - \frac{8x³y}{(x⁴+y⁴)}$

$4xy*(\frac{1}{(x²-y²)}+\frac{1}{(x²+y²)}) - \frac{8x³y}{(x⁴+y⁴)}$

$4xy*(\frac{(x²+y²+x²-y²)}{(x²-y²)(x²+y²)}) - \frac{8x³y}{(x⁴+y⁴)}$

$4xy*(\frac{2x²}{(x⁴-y⁴)}) - \frac{8x³y}{(x⁴+y⁴)}$

$\frac{8x³y}{(x⁴-y⁴)} - \frac{8x³y}{(x⁴+y⁴)}$

$8x³y \times [\frac{1}{(x⁴-y⁴)} - \frac{1}{(x⁴+y⁴)}]$

$8x³y \times \frac{(x⁴+y⁴-x⁴+y⁴)}{(x⁴-y⁴)(x⁴+y⁴)}$

$8x³y \times \frac{2y⁴}{(x⁸-y⁸)}$

$\frac{16x³y⁵}{(x⁸-y⁸)}$