Question

solve it fast no copied​

Answer 1

$\huge\green{\boxed{\mathfrak{refer \: the \: attachment}}}$

Steps Followed

• Simplify LHS and RHS seperately

• In LHS change tanA in the form of secA and then in form of cosA using identity

$seca = \frac{1}{cosa}$

• Change tanA in the form of cosA/sinA using identity

$tana = \frac{sina}{cosa}$

• Then reciprocal the denominator and cut down cos^2A with cos^2A and sin^2A with sin^2A

• Add the equation taking LCM

• In numerator write 1 using identity

${sin}^{2} a + {cos}^{2} a = 1$

• Change sin^2A in the form of cosA using identity

${sin}^{2} a = 1 - {cos}^{2} a$

• Then you will find LHS is equal to

$\frac{1}{1 - 2 {cos}^{2}a }$

• RHS is already

$\frac{1}{1 - 2 {cos}^{2}a }$

• Here LHS=RHS

• Hence proved