Question

solve it fast please​

Answer 1

Answer:

option 3

Explanation:

flux through all phases = q/epsilon

therefore flux through one phase of cube= q/6 epsilon

Answer 2

GiveN :-

A charge q is situated at the centre of a cube.

TO FinD :-

The electric flux through one of the faces of the cube.

AcknowledgemenT :-

Cube has six equal faces, so electric flux passing through each face would be equal.

SolutioN :-

Let "A" be the area of the face, and "E" be the field intensity.

Total flux = 6(E × A) = q/ε₀

Then, the net electric flux passing through each face of the cube is given by

EA = (q/ε) ÷ 6

⇒EA = q/6ε₀

So, the answer is (3) q/6ε₀.