Question

solve it fast please​

Answer 1

Answer:

==> (1+2i)/1-(1-1-2i). r=√(x^2 + y^2)

==> (1+2i)/1+2i)

==> 1= 1+0.i

amplitude= tan Inverse (x/y)

tan Inverse(1/0)= 0

option b is correct

Answer 2

Answer:

option b)1 and 0

Here ,1+2i/1-(1-i)^2

=1+2i/1-(1-2i+i^2)

=1+2i/1-1+2i+1. [i^2=-1]

=1+2i/ 1+2i

=1

=1+0.i

and amplitude tanα=y/x

α=tan^-1(tan0/1)

α=tan^-1(tan0)

α=0