Question

Solve it fast please
No irrelevant answers​

Answer 1

Answer:

make this question understanding because I am not able to read it language

Answer 2

PT = y√(1+ cot2 θ )=y√(1+(dx/dy)2 ). Also, PN = y sec q = y√(1+tan2 θ )=y√(1+(dy/dx)2 ). => Length of the normal, PN = |y| √(1+(dy/dx)2 ).