Question

solve it fast plz with step by step explanation

Answer 1

Answer:

Thevalueof

sin48sec42+cos48cosec42

=2

Step-by-step explanation:

\begin{lgathered}The \: value \: of \:\\ sin48sec42+cos48cosec42\\ =sin(90-42)sec42\\+cos(90-42)cosec42\\ =cos42sec42+sin42cosec42\\ =cos42\times \frac{1}{cos42}+sin42\times \frac{1}{sin42}\\ =1+1\end{lgathered}

Thevalueof

sin48sec42+cos48cosec42

=sin(90−42)sec42

+cos(90−42)cosec42

=cos42sec42+sin42cosec42

=cos42×

cos42

1

+sin42×

sin42

1

=1+1

Therefore,

\begin{lgathered}The \: value \: of \:\\ sin48sec42+cos48cosec42\\=2\end{lgathered}

Thevalueof

sin48sec42+cos48cosec42

=2