Question

solve it fast plzzzzz​

Answer 1

Answer:

√2 - 1

or

1-√2

Step-by-step explanation:

$\sqrt{3 - 2 \sqrt{2} } \\ \\ = \sqrt{2 + 1 - 2 \sqrt{2} } \\ \\ = \sqrt{ { (\sqrt{2} ) }^{2} + {1}^{2} - 2 \sqrt{2} \times (1 )} \\ \\ = \sqrt{ { (\sqrt{2} - 1)}^{2} } \\ \\ = \sqrt{2} - 1 \:$

Again it can be done as :

$\sqrt{3 - 2 \sqrt{2} } \\ \\ = \sqrt{1 + 2 - 2 \sqrt{2} } \\ \\ = \sqrt{ {1}^{2} + { (\sqrt{2} })^{2} - 2 \times 1 \times( \sqrt{2} )} \\ \\ = \sqrt{ ({1 - \sqrt{2} )}^{2} } \\ \\ = 1 - \sqrt{2}$

Answer 2

the correct answer is (√2-1)or (1-√2)