Math, asked by ItzShrestha41, 6 hours ago

Solve it fast ^^

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Answered by Anonymous
3

Value of k is \dfrac{15}{4}

Explanation:

Given equation: 3x^{2}+2kx+3=0

Since x=-\dfrac{1}{2} is one of its roots, then it satisfies the above equation

\Rightarrow 3(-\dfrac{1}{2})^{2}+2k(-\dfrac{1}{2})+3=0

\Rightarrow \dfrac{3}{4}-k+3=0

\Rightarrow k=\dfrac{3}{4}+3

\Rightarrow k=\dfrac{3+3\times 4}{4}

\Rightarrow k=\dfrac{3+12}{4}

\Rightarrow k=\dfrac{15}{4}

Answered by XxSrishtiRajputxX
4

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Step-by-step explanation:

thank u so much for thanks..✌✌

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