Question

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Answer 1

Step-by-step explanation:

(i) AB=CD

(opposite sides of rectangle are equal)

(ii) angle BPA=angle DQC

(Each 90 [given BP and DQ is perpendicular to AC])

(iii)

It is given that in parallelogram ABCD, BP is perpendicular to AC and DQ is perpendicular to AC.

In ΔADQ and ΔCBP,

AD=CD  (Opposite sides of a parallelogram)

∠DAQ=∠BCP and AD∣∣BC,AC  (Transversal alternate angles)

∠DQA=∠BPC=900  (Given)

⸫ΔADQ=ΔCBP         (SAA)

(iv)BP =DQ (By C.P.C.T.C)

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