Question

solve it for 50 points spam will be reported​

Answer 1

Answer:

${\longrightarrow{\boxed{\sf{x = \dfrac{-6 \pm \sqrt{-4}}{2}}}}}$

Step-by-step explanation:

$\longrightarrow\sf{x^{2} + 6x + 10 = 0}$

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here,

• a = 1,
• b = 6,
• c = 10.

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So,

$\longrightarrow\sf{1x^{2} + 6x + 10 = 0}$

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Using quadratic formula:

★ ${\boxed{\sf{x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}}}$ ★

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Calculations:-

$\longrightarrow\sf{x = \dfrac{-(6) \pm \sqrt{(6)2 - 4(1)(10)}}{2(1)}}$

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${\longrightarrow{\boxed{\sf{x = \dfrac{-6 \pm \sqrt{-4}}{2}}}}}$

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Therefore, this is the required answer.

Answer 2

★FIND:

The value of 'x'

★GIVEN,

$\bold{x^2+6x+10=0}$

★SOLUTION:

$\bold{x^2+6x+10=0}$

$\bold{where, }$

$\bold{a=1,}$ $\bold{b=6,}$ $\bold{c=10}$

$x = \frac{ - b + - \sqrt{b {}^{2} - 4ac} }{2a}$

$x = \frac{ - 6 + - \sqrt{36 - 4(1)(10)} }{2(1)} \\ = \frac{ - 6 + - \sqrt{36 - 40} }{2} \\ = \frac{ - 6 + - \sqrt{ - 4} }{2} \\ = \frac{ - 6 + - \sqrt{4i {}^{2} } }{2} \\ (i {}^{2} = - 1) \\ = \frac{ - 6 + - \sqrt{4}i }{2} \\ = \frac{ - 6 + - 2i}{2} \\ = - 3 + - i \\ x = - 3 + - i$