Math, asked by drbrainly98, 4 months ago

solve it for brainlist..​

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Answered by BrainlyEmpire
102

GIVEN :-

  • A tunning fork makes 256 vibrations per second in air .

  • The speed of sound is 330m/s .

TO FIND :-

  • The wavelength of sound .

SOLUTION :-

  • \huge\green\star \bf\pink{\lambda\:=\:\dfrac{c}{\nu}\:}

Where,

\bf\red{\lambda} = Wavelength

\bf\red{c} = Speed of sound

\bf\red{\nu} = Frequency

☯︎ According to the question,

\bf\red{c} = 330 m/s

\bf\red{\nu} = 256 vibration per second

\rm{:\implies\:\lambda\:=\:\dfrac{330}{256}\:}\:\\

\bf\blue{:\implies\:\lambda\:=\:1.289\:m\:\approx\:1.29\:m}\:\\ \\

\huge\red\therefore The wavelength of sound is "1.29m" .

Answered by Anonymous
65

Answer:

GIVEN :-

A tunning fork makes 256 vibrations per second in air .

The speed of sound is 330m/s .

TO FIND :-

The wavelength of sound .

SOLUTION :-

\huge\green\star \bf\pink{\lambda\:=\:\dfrac{c}{\nu}\:}

Where,

\bf\red{\lambda} = Wavelength

\bf\red{c} = Speed of sound

\bf\red{\nu} = Frequency

☯︎ According to the question,

\bf\red{c} = 330 m/s

\bf\red{\nu} = 256 vibration per second

\rm{:\implies\:\lambda\:=\:\dfrac{330}{256}\:}\:\\

\bf\blue{:\implies\:\lambda\:=\:1.289\:m\:\approx\:1.29\:m}\:\\ \\

\huge\red\therefore The wavelength of sound is "1.29m" .

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