Solve it for me please help me in this question
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Answered by
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Sakshi bidwe (patil)
4/x + 3y. =8
and
6/x - 4y. =-5
let us consider tha m= 1/ x si
4m + 3y. =8
6m - 4y = -5
m. = 8-3y/4
6(8-3y/4) - 4y = -5
48-18y -16y. = -20
- 34y. = -20-48
34y. =68
y. = 2 an
m. =1/2
m. = 1/x
1/2. =1/x
x. =2
hope it help
be brainly@
4/x + 3y. =8
and
6/x - 4y. =-5
let us consider tha m= 1/ x si
4m + 3y. =8
6m - 4y = -5
m. = 8-3y/4
6(8-3y/4) - 4y = -5
48-18y -16y. = -20
- 34y. = -20-48
34y. =68
y. = 2 an
m. =1/2
m. = 1/x
1/2. =1/x
x. =2
hope it help
be brainly@
Tushar099:
You are still awake in thanks for doing my question
Answered by
1
Answer: x= 2, y=2
Step-by-step explanation:
Let us solve the given equation by elimination method
4/x + 3y = 8 .....(i)
6/x - 4y = -5 .....(ii)
Multiply equation (i) by 4 && equation (ii) by 3
(i)==== 16/x + 12y = 32
(ii)=== 18/x - 12y = -15
Add above equations:
16/x + 18/x = 32+-15
34/x = 17
x = 34/17 = 2
substitute the value of 'x' in any equation
'x' in (i)
4/2 + 3y = 8
2 + 3y = 8
3y = 8-2=6
y = 6/3 = 2
x=2 && y=2
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