Math, asked by Tushar099, 1 year ago

Solve it for me please help me in this question

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Answers

Answered by SakshiBidwe
1
Sakshi bidwe (patil)

4/x + 3y. =8

and

6/x - 4y. =-5

let us consider tha m= 1/ x si

4m + 3y. =8
6m - 4y = -5

m. = 8-3y/4
6(8-3y/4) - 4y = -5
48-18y -16y. = -20

- 34y. = -20-48
34y. =68
y. = 2 an
m. =1/2
m. = 1/x
1/2. =1/x
x. =2

hope it help

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Answered by Anonymous
1

Answer: x= 2, y=2

Step-by-step explanation:

Let us solve the given equation by elimination method

4/x + 3y = 8 .....(i)

6/x - 4y = -5 .....(ii)

Multiply equation (i) by 4 && equation (ii) by 3

(i)==== 16/x + 12y = 32

(ii)===  18/x - 12y = -15

Add above equations:

16/x + 18/x = 32+-15

34/x = 17

x = 34/17 = 2

substitute the value of 'x' in any equation

'x' in (i)

4/2 + 3y = 8

2 + 3y = 8

3y = 8-2=6

y = 6/3 = 2

x=2 && y=2

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