Question

solve it form factorisation

Answer 1

abx² + b²x - acx - bc = 0
abx² - acx + b²x - bc = 0
ax ( bx - c ) + b (bx - c ) = 0
( bx - c ) + ( ax + b ) = 0 

Answer 2

31.

⇒ abx² + ( b² - ac )x - bc = 0

⇒ abx² + b²x - acx - bc = 0

Taking out bx as common from first 2 terms and c from last 2 terms.

⇒bx ( ax + b ) - c ( ax + b ) = 0

⇒ ( ax + b ) ( bx - c ) = 0

⇒ ( ax + b ) = 0 ÷ ( bx - c )

⇒ ax + b = 0

⇒ax = -b

•°• x = -b/a

" Or "

⇒ ( ax + b ) ( bx - c ) = 0

⇒( bx - c ) = 0 ÷ ( ax + b )


⇒ ( bx - c ) = 0

⇒ bx = c

•°• x = c/b

Hence, x = ( -b/a ) or ( c/b ).

Factorized form : ( ax + b ) ( bx - c ).