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Given a conical tent with
Height ( h ) = 8m
Radius ( r ) = 6m
So its slant height⇒ √( h² + r²)
⇒ √ 64 + 36
⇒ √100
⇒ 10 m
We know that curved surface area of the cone = π* r* l
= 3.14 * 6 * 10
= 188.4 m²
Now, given that the extra length of material required for stiching margins and wastages in cutting is approx. 20 cm = 0.2m
So length = ( l - 0.2 m)
Width = 3m (given)
The area of the trapaulln = l x b = ( l - 0.2) (3)
We know that Area of sheet = CSA of tent
So ( l - 0.2) (3) = 188.4 m²
⇒ 3l - 0.6 = 188.4
⇒ l = (188.4 + 0.6) /3
⇒ l = 189 / 3
⇒ l = 63 m
Your answer = 63m
Height ( h ) = 8m
Radius ( r ) = 6m
So its slant height⇒ √( h² + r²)
⇒ √ 64 + 36
⇒ √100
⇒ 10 m
We know that curved surface area of the cone = π* r* l
= 3.14 * 6 * 10
= 188.4 m²
Now, given that the extra length of material required for stiching margins and wastages in cutting is approx. 20 cm = 0.2m
So length = ( l - 0.2 m)
Width = 3m (given)
The area of the trapaulln = l x b = ( l - 0.2) (3)
We know that Area of sheet = CSA of tent
So ( l - 0.2) (3) = 188.4 m²
⇒ 3l - 0.6 = 188.4
⇒ l = (188.4 + 0.6) /3
⇒ l = 189 / 3
⇒ l = 63 m
Your answer = 63m
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